u^2+14u+14=0

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Solution for u^2+14u+14=0 equation:


Simplifying
u2 + 14u + 14 = 0

Reorder the terms:
14 + 14u + u2 = 0

Solving
14 + 14u + u2 = 0

Solving for variable 'u'.

Begin completing the square.

Move the constant term to the right:

Add '-14' to each side of the equation.
14 + 14u + -14 + u2 = 0 + -14

Reorder the terms:
14 + -14 + 14u + u2 = 0 + -14

Combine like terms: 14 + -14 = 0
0 + 14u + u2 = 0 + -14
14u + u2 = 0 + -14

Combine like terms: 0 + -14 = -14
14u + u2 = -14

The u term is 14u.  Take half its coefficient (7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
14u + 49 + u2 = -14 + 49

Reorder the terms:
49 + 14u + u2 = -14 + 49

Combine like terms: -14 + 49 = 35
49 + 14u + u2 = 35

Factor a perfect square on the left side:
(u + 7)(u + 7) = 35

Calculate the square root of the right side: 5.916079783

Break this problem into two subproblems by setting 
(u + 7) equal to 5.916079783 and -5.916079783.

Subproblem 1

u + 7 = 5.916079783 Simplifying u + 7 = 5.916079783 Reorder the terms: 7 + u = 5.916079783 Solving 7 + u = 5.916079783 Solving for variable 'u'. Move all terms containing u to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + u = 5.916079783 + -7 Combine like terms: 7 + -7 = 0 0 + u = 5.916079783 + -7 u = 5.916079783 + -7 Combine like terms: 5.916079783 + -7 = -1.083920217 u = -1.083920217 Simplifying u = -1.083920217

Subproblem 2

u + 7 = -5.916079783 Simplifying u + 7 = -5.916079783 Reorder the terms: 7 + u = -5.916079783 Solving 7 + u = -5.916079783 Solving for variable 'u'. Move all terms containing u to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + u = -5.916079783 + -7 Combine like terms: 7 + -7 = 0 0 + u = -5.916079783 + -7 u = -5.916079783 + -7 Combine like terms: -5.916079783 + -7 = -12.916079783 u = -12.916079783 Simplifying u = -12.916079783

Solution

The solution to the problem is based on the solutions from the subproblems. u = {-1.083920217, -12.916079783}

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